For part C) Sourcelin the figure emits electromagnetic radiation of 15 MHz Sourc
ID: 2107932 • Letter: F
Question
For part C)
Explanation / Answer
a) s=ExB/muo. B=E/C for em radiation. so, Power/area = E^2/2cmuo avg. Which gives E=7.7x10^5 N/c and B=2.53x10^-3T.
b)a=40cm and b=30cm so c=50cm (triangle lenghts). wavelength=c/frequency. for15Mhz, lambda=20m. (.50-.40)/20=0.005. Phase=pi/100.
c)
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