A 12.69 g ice cube at -6.33 o C is place in an aluminum cup whose initial temper

Question

1. A 12.69 g ice cube at -6.33 oC is place in an aluminum cup whose initial temperature is 135.39 oC. The system comes to an equilibrium temperature of 16.7 oC. What is the mass in grams of the cup? The specific heat of ice is 2.093 J/g oC and that of aluminum is 0.901 J/g oC. Answer

Explanation / Answer

Apply conservation of energy

mc(delta T) + mH + mc(detla T) of the ice = mc(delta T) of the cup

(12.69)(2.093)(6.33) + (12.69)(333) + (12.69)(4.186)(16.7) = (m)(.901)(135.39-16.7)

m = 49.4 grams

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