Any help would be great! Will rate! Thanks! Nothing to transcribe Wire loop fall
ID: 2106724 • Letter: A
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Any help would be great! Will rate! Thanks!
Nothing to transcribe Wire loop falling in a magnetic field The upper part of a rectangular wire loop is intercepted by a homogeneous magnetic field, perpendicular to the plane of the paper, of strength B. The lower part of the loop experiences no field. The wire loop, whose ohmic resistance is R, is found to fall with constant speed v. Calculate the magnitude of the current flow induced in the loop as a result of the fall with constant speed. Express I in terms of B, l, v, and R. Calculate the Lorentz force on the current loop, and show that the force is upwards. Express the force in terms of B, l, v, and R. The magnitude of v is determined by a balance between mg and the Lorentz force. Use this to obtain a formula for v in terms of m, g, B, l, and R. Calculated numerically the speed of fall if l = 10 cm, m = 1.8 g, R = 0.68x10 -2 ohm. (The wire is #15 gauge aluminum.) The magnetic field is produced by an electromagnetic and B = 1 T. How would the value of v be changed if: The wire was twice as thick. The loop contained two turns. The magnetic field was doubled. The linear dimensions of the loop were doubled.Explanation / Answer
A) Current = B*l*v / R, B) lorentz Force = i*l x B =( Blv/R) *l x B = B^2* l^2 *v /R, C) For balancing mg = lorentz force , so B^2* l^2 *v /R = mg, so v = mgR/B^2*l^2, D) 0.0119m/s. E) a) resistance will decrease due to thick wire so speed will also decrease b) speed will decrease c) decrease d)decrease.
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