The starship Enterprise leaves a distant earth colony, which is nearly at rest w

Question

The starship Enterprise leaves a distant earth colony, which is nearly at rest with respect to the earth. The ship travels at nearly constant velocity toward earth. When the Enterprise reaches earth 1.04 y has elapsed, as measured on the ship. Clocks in the earth's reference frame show that the voyage lasted 3.29 y.

How far from earth is the colony, as measured in the reference frame of the earth?

(b) How far from earth is the colony, as measured in the reference frame of the ship?

Thank you in advance.

Explanation / Answer

Gamma = / _rest / / _moving = 3.29/1.04 = 3.16

So, 3.163 = 1 / sqrt( 1 - (v/c)^2),
(1 / 3.163)^2 = 1 - (v/c)^2,
v/c = sqrt( 1 - (1/3.163)^2 ) = 0.948
v = 0.9487 * c

Once you know v, then
a) distance = speed (v) * time (3.29 rest frame years)
         =0.9487 c*3.29 years
v is the same for the moving frame so...
b) distance = speed (v) * time (1.04 moving frame years)

         0.9487 c*1.04 years

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