A spring, of negligible mass and which obeys Hooke\'s Law, supports a mass M on
ID: 2105668 • Letter: A
Question
A spring, of negligible mass and which obeys Hooke's Law, supports a mass M on an incline which has negligible friction. The figure below shows the system with mass M in its equilibrium position. The spring is attached to a fixed support at P. The spring in its relaxed state is also illustrated.
1-Mass M has a value of 235 g. Calculate k, the spring constant.
2-The mass oscillates when given a small displacement from its equilibrium position along the incline. Calculate the period of oscillation.
Please include the calculations.
Explanation / Answer
angle with horizontalÂ
tan(theta) = 60/80 Â = 3/4
sin(theta) = 3/5
stretching of spring = 50-20 = 30 cm
balancing the force
kx= mgsin(theta)
k * 3 x 10^-1 Â = 235 x 10^-3 * 9.81 * 3/5
k = 4.6107 N/m
w = 2pi/ sqrt(k/m)
= 1.4185 s
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