A .005 kg block having a velocity of 500 m/s hits a 5 kg wooden block at rest on

Question

A .005 kg block having a velocity of 500 m/s hits a 5 kg wooden block at rest on a horizontal at an angle of 30 degrees from the horizontal . Find the speed of the block after being hit by the bullet.

Explanation / Answer

applying momentum conservation in horizontal direction; 0.005* 500 * cos 30 = (0.005 +5) Vx => Vx = 0.433 m/s applying conservation of momentum in vertical direction; 0.005* 500*sin 30 =(0.005+5) Vy =>Vy = 0.25 m/s total velocity of block = sqrt(0.25^2 +0.433^2) = 0.5 m/s angle made with horizontal = tan^-1(0.25/0.433) = 29.985 degrees the block moves with a speed of 0.5 m/s at an angle of 29.985 degrees with the horizontal.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.