A 0.331-kg box is placed in contact with a spring of stiffness 2.639×10 2 N/m.

Question

A 0.331-kg box is placed in contact with a spring of stiffness 2.639×102 N/m. The spring is compressed 1.19×10-1 m from its unstrained length. The spring is then released, the block slides across a frictionless tabletop, and it flies through the air. The tabletop is a height of 1.210 m above the floor.

(the drawing is not to scale) What is the potential energy stored in the spring when it is compressed?
1.87 J

What is the kinetic energy of the block just before it leaves the table but after it is no longer in contact with the spring?
1.87 J

What is the kinetic energy of the block just before it hits the floor?
5.79 J

How much time elapses between the time when the block leaves the table and the time just before the block hits the floor?
4.97×10-1 s

I need the following answered

What distance, d, from the edge of the table does the block hit the floor?

Explanation / Answer

time taken by the body to reach the ground is found by using

s=0.5*a*t^2

t=sqrt(2s/a)

s=1.21 m

a=9.8 m/sec

t=0.35138 sec

now range x=u*t

kinetic energy=1.87 J=0.5*m*v^2

v=11.29 m/sec

tis gives x=3.97 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.