thanks A low intensity light with certain wavelength lambda. illuminates a surfa

Question

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A low intensity light with certain wavelength lambda. illuminates a surface of metal, but no photoelectrons are observed. (Photoelectrons: electrons that are pushed out from metal by light.) To observe photoelectrons, you need to: (2%) Decrease the intensity of light * (62%) Use light with shorter wavelength (30%) Increase the intensity of light (6%) Use light with longer wavelength To Kick electrons you need more energetic photons E=hf Higher frequency Lower wavelength Wc = hfc = h c / lambda c

Explanation / Answer

from einstein photoelectric effect theory

(K.E)max=hc/lemda - work function

clearly kinetic energy of electron depends only on wavelength of light for same material

hence answer is

b)use light with shorter wavelength

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