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X rays with a wavelength of 0.18 nm undergo first-order diffraction from a cryst

ID: 2104549 • Letter: X

Question

X rays with a wavelength of 0.18 nm undergo first-order diffraction from a crystal at a 74 degree angle of incidence. 1) What is the angle of second-order diffraction? I have attempted this problem many times but still cannot find the correct answer. Do NOT copy and paste solutions from the internet or other Chegg questions. X rays with a wavelength of 0.18 nm undergo first-order diffraction from a crystal at a 74 degree angle of incidence. 1) What is the angle of second-order diffraction? I have attempted this problem many times but still cannot find the correct answer. Do NOT copy and paste solutions from the internet or other Chegg questions.

Explanation / Answer

in braggs law angle is wrt horizontal. but in general we say angle of incidence wrt normal(vertical). so take theta =90-74=16

m = 1

, d = m*lambda/(2sin(16))
For m = 2
? = arcsin(2*lambda/(2d))

=arcsin(2*lambda/(2lambda/(2sin(16)))

=arcsin(2sin(16))

=33.45degrees