The graph shows the US Department of Labor noise regulation for working without
ID: 2103691 • Letter: T
Question
The graph shows the US Department of Labor noise regulation for working without ear protection. A machinist is in an environment where the ambient sound level is of 85 dB, i.e., corresponding to the 8 Hours/day noise level. The machinist likes to listen to music, and plays a Boom Box at an average level of 84.0 dB.
A student at a rock concert has a seat close to the speaker system, where the average sound intensity corresponds to a sound level of 114 dB. By what factor does that sound intensity exceed the 1.5- Hours/day intensity limits from the graph?
Explanation / Answer
f(x) = permisible noise Hour/day = 8e^[0.138(x-85)] , where x =db
f(x) = 8e^[0.138(x-85)]
at x= 114 db , F(x) = 0.146 Hour/day
when intensity = 1.5 , tehn
1.5 =8e^[0.138(x-85)]
x = 72.86 db
hence sound intensity at 1.5 Hour/day = 72.86 db
factor = 72.86/114 =0.63
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