a) Look at the diagram in the Basic Concepts part of the lab, under Equilibrium.

Question

a) Look at the diagram in the Basic Concepts part of the lab, under Equilibrium. Two forces act on opposite ends of a uniform rod of mass m and length L, in opposite directions. The rod is supported by a fulcrum at the center, which is the axis of rotation. The force and torque exerted by the fulcrum on the rod are F = mg, ? = FL/2F = mg + F, ? = FL/2    F = mg, ? = 2FLF = mg, ? = FLF = mg, ? = 0F = 0, ? = FL/2F = 0, ? = FLF = 0, ? = 2FLF = mg + F, ? = 2FLF = mg + F, ? = 0F = mg + F, ? = FLF = 0, ? = 0
b) In procedure 2, you balance the ruler. If the density of the ruler increases without changing its dimensions (and remaining uniform), the ruler will tip toward m2be unbalanced, but the direction depends on the hanging masses, the mass of the ruler, and distances    still be balancedtip toward m1
c) In procedure 3, you balance the ruler. If the density of the ruler increases without changing its dimensions, the ruler will be unbalanced, but the direction depends on the hanging mass, the mass of the ruler, and distancestip toward m     tip away from mstill be balanced 2. a) Look at the diagram in the Basic Concepts part of the lab, under Equilibrium. Two forces act on opposite ends of a uniform rod of mass m and length L, in opposite directions. The rod is supported by a fulcrum at the center, which is the axis of rotation. The force and torque exerted by the fulcrum on the rod are F = mg, ? = FL/2F = mg + F, ? = FL/2    F = mg, ? = 2FLF = mg, ? = FLF = mg, ? = 0F = 0, ? = FL/2F = 0, ? = FLF = 0, ? = 2FLF = mg + F, ? = 2FLF = mg + F, ? = 0F = mg + F, ? = FLF = 0, ? = 0
b) In procedure 2, you balance the ruler. If the density of the ruler increases without changing its dimensions (and remaining uniform), the ruler will tip toward m2be unbalanced, but the direction depends on the hanging masses, the mass of the ruler, and distances    still be balancedtip toward m1
c) In procedure 3, you balance the ruler. If the density of the ruler increases without changing its dimensions, the ruler will be unbalanced, but the direction depends on the hanging mass, the mass of the ruler, and distancestip toward m     tip away from mstill be balanced 2. a) Look at the diagram in the Basic Concepts part of the lab, under Equilibrium. Two forces act on opposite ends of a uniform rod of mass m and length L, in opposite directions. The rod is supported by a fulcrum at the center, which is the axis of rotation. The force and torque exerted by the fulcrum on the rod are F = mg, ? = FL/2F = mg + F, ? = FL/2    F = mg, ? = 2FLF = mg, ? = FLF = mg, ? = 0F = 0, ? = FL/2F = 0, ? = FLF = 0, ? = 2FLF = mg + F, ? = 2FLF = mg + F, ? = 0F = mg + F, ? = FLF = 0, ? = 0
b) In procedure 2, you balance the ruler. If the density of the ruler increases without changing its dimensions (and remaining uniform), the ruler will tip toward m2be unbalanced, but the direction depends on the hanging masses, the mass of the ruler, and distances    still be balancedtip toward m1
c) In procedure 3, you balance the ruler. If the density of the ruler increases without changing its dimensions, the ruler will be unbalanced, but the direction depends on the hanging mass, the mass of the ruler, and distancestip toward m     tip away from mstill be balanced a) Look at the diagram in the Basic Concepts part of the lab, under Equilibrium. Two forces act on opposite ends of a uniform rod of mass m and length L, in opposite directions. The rod is supported by a fulcrum at the center, which is the axis of rotation. The force and torque exerted by the fulcrum on the rod are F = mg, ? = FL/2F = mg + F, ? = FL/2    F = mg, ? = 2FLF = mg, ? = FLF = mg, ? = 0F = 0, ? = FL/2F = 0, ? = FLF = 0, ? = 2FLF = mg + F, ? = 2FLF = mg + F, ? = 0F = mg + F, ? = FLF = 0, ? = 0
b) In procedure 2, you balance the ruler. If the density of the ruler increases without changing its dimensions (and remaining uniform), the ruler will tip toward m2be unbalanced, but the direction depends on the hanging masses, the mass of the ruler, and distances    still be balancedtip toward m1
c) In procedure 3, you balance the ruler. If the density of the ruler increases without changing its dimensions, the ruler will be unbalanced, but the direction depends on the hanging mass, the mass of the ruler, and distancestip toward m     tip away from mstill be balanced F = mg, ? = FL/2F = mg + F, ? = FL/2    F = mg, ? = 2FLF = mg, ? = FLF = mg, ? = 0F = 0, ? = FL/2F = 0, ? = FLF = 0, ? = 2FLF = mg + F, ? = 2FLF = mg + F, ? = 0F = mg + F, ? = FLF = 0, ? = 0 tip toward m2be unbalanced, but the direction depends on the hanging masses, the mass of the ruler, and distances    still be balancedtip toward m1 be unbalanced, but the direction depends on the hanging mass, the mass of the ruler, and distancestip toward m     tip away from mstill be balanced 2. 2. 2.

Explanation / Answer

considering the first question we can say that that since force is equal to mass times gravity F= mg. On the other hand torque here is 0.

u can see that from ur lab..

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