According to one estimate, there are 4.4 x 10^6 metric tons of world uranium res

Question

According to one estimate, there are 4.4 x 10^6 metric tons of world uranium reserves extractable at $89.00/kg or less. About 0.7% of naturally occuring uranium is the fissionable isotope 235U. (a) Calculate the mass of 235U in this reserve in grams. (b) Find the number of moles of 235U and convert to a number of atoms. (c) Assuming 202.5 MeV is obtained from each reaction and all this energy is captured, calculate the total energy that can be extracted from the reserve in joules. (d) Assuming world power consumption to be constant at 1.5 x 10^13 J/s, how many years could the uranium reserves provide for all the world's energy needs using conventional reactors that don't generate nuclear fuel? (e) What conclusions can be drawn?

Explanation / Answer

for 100 percentage 4.4 *10^6

for 0.7 percentage it will be 0.7/100 *4.4*10^6 metric tons=0.0308 metric tons

no of moles =weight /molecular weight=0.0308 *10^9 kg/238=1.29 *10^5 moles

no of atoms= m*N/M=0.0308*6.023*10^23*10^3/(238)= 7.79 *10^22 atoms

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