Deflection of the electron beam in a tube TV set is accomplished by magnetic for

Question

Deflection of the electron beam in a tube TV set is accomplished by magnetic forces. The electrons are accelerated until they have kinetic energy 25 keV (a kilo-electron-volt (1 keV) is the energy needed to accelerate a single electron, with charge -e, across a potential difference of -1 kiloVolts). What magnetic field is required to produce a deflection of 3.3 cm if the magnetic field region is 8.0 cm long? If there is a 22 cm gap between the end of the magnetic field region and the end of the tube, how far from the center of the screen does the beam strike?

Please show all steps.

The answer should be:

field magnitude = 4.699 x 10^3 T

total deflection = 25.16 cm

Explanation / Answer

use the formulae

ynet = y1 + y2

R = mv/qB

R = (m/eB)*?(2eVacc/m)R = (m/eB)*?(2eVacc/m)

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