A jellyfish is floating in a water-filled aquarium 1.48 m behind a flat pane of

Question

A jellyfish is floating in a water-filled aquarium 1.48 m behind a flat pane of glass 5.90 cm thick and having an index of refraction of 1.5. (The index of refraction of water is 1.33.)

(a) Where is the image of the jellyfish located? (Find the location of the final image, taking the inside and outside surfaces of the pane of glass as two refracting surfaces. Use a negative number to indicate the image is in the tank. Measure the distance from the air-glass interface. Enter your answer to three decimal places.)

(b) Repeat the problem when the glass is so thin that its thickness can be neglected. (Use a negative number to indicate the image is in the tank. Enter your answer to three decimal places.)

Explanation / Answer

   For the flat plane of glass radius R approaches infinity         so        n 1 / P   = - n2 / Q      here   P is distance between object and mirror             Q is distance between image and water                       n 1 is refractive index of water              n 2 is refractive index of air             image distance                      Q = -(    n2 / n1 ) P                             =   - ( 1 / 1.33 ) 1                         =    -0.7518 m a) the distance between image and outer surface of gless is    q = -0.7518 + 0.059                                                                                                        = 0.8108 b)when the glass is so thin that its thickness can be neglected q = - 0.7518 m c) The thicker the glass,greater the distance between the final image and the outer surface of the        glass   

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