Suppose a beam of 4.00 eV protons strikes a potential energy barrier of height 5

Question

Suppose a beam of 4.00 eV protons strikes a potential energy barrier of height 5.80 eV and thickness 0.670 nm, at a rate equivalent to a current of 880 A. How many years would you have to wait (on average) for one proton to be transmitted through the barrier?

I will note that I have checked similar posted questions and while they may be right I still keep getting a wrong answer. Unless I made a conversion mistake I have no idea what I am doing wrong.

Basically, if you can supply me with an equation and conversions along with the final answer I would appreciate it.

Note: you don't have to go into gory detail unless you want to do so. Thanks for your time.

Explanation / Answer

T = 16*(E/V)(1-E/V) *exp(-2*a*k)

K = sqrt(2*m*(V-E)/(h/(2*pi))^2)

a= .67 nm

m = 1.67*0^-27 kg

V = 5.8 ev

E = 4 ev

h-> planck's constant

T gives the transmission coefficient = (no of particlesthat pass)/(no of incident particles)

=> T*880 = )noof particles that pass per sec.

hence ur ans would be 1/(T*880

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