Satellites like the Hubble Space Telescope (11,000 kg) orbit about 200 km above

Question

Satellites like the Hubble Space Telescope (11,000 kg) orbit about 200 km above the surface of the Earth in circular orbits. Tiny amounts of air drag from the upper atmosphere cause the satellite to lose speed and the orbit eventually decreases to 150 km (also in a circular orbit). Find the speed of the satellite in its initial orbit and the final orbital speed. Show whether the satellite has gained or lost energy (consider kinetic and potential). What force is responsible for the change in speed?

show me details please? or steps

Explanation / Answer

a. V0 = sqrt (GMe/R+h)

V0 = sqrt (6.67*10^-11 * 6*10^24 /(6400+200)*1000

V0 = 7.786 km/s

b. V0 = sqrt (6.67*10^-11 * 6*10^24 /(6400+150)*1000 = 7.816 kmn/s

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