In an L-R-C series circuit L = 0.330 H, R =380.0 ohm, and C = 7.20 mu F. The AC

Question

In an L-R-C series circuit L = 0.330 H, R =380.0 ohm, and C = 7.20 mu F. The AC source is operating at the resonance and has a voltage amplitude of 250.0 V . Find (a) the instantaneous voltage across R, L, and C respectively; (b) find the average power of the AC circuit. In an L-R-C series circuit L = 0.330 H, R =380.0 ohm, and C = 7.20 mu F. The AC source is operating at the resonance and has a voltage amplitude of 250.0 V . Find (a) the instantaneous voltage across R, L, and C respectively; (b) find the average power of the AC circuit.

Explanation / Answer

a. V = 250 volts b. w = 1/rt (LC) = 1/ rt (0.330*7.2 *10^-6) = 648 rad/s avg power = V^2/R = 250*250/2*380 power avg = 82.23 W

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