A) When the cylinder reaches the bottom of the ramp, what is its total kinetic e

Question

A) When the cylinder reaches the bottom of the ramp, what is its total kinetic energy? Express your answer using two significant figures. B)When the cylinder reaches the bottom of the ramp, what is its rotational kinetic energy? C)When the cylinder reaches the bottom of the ramp, what is its translational kinetic energy? Express your answer using two significant figures. B)When the cylinder reaches the bottom of the ramp, what is its rotational kinetic energy? C)When the cylinder reaches the bottom of the ramp, what is its translational kinetic energy?

Explanation / Answer

First find the velocity.

sq-root((gh)/0.75) = velocity m/s

sq-rt((9.8 x 0.85)/0.75) = 3.33 m/s

b.) When the cylinder reaches the bottom of the ramp, what is its rotational kinetic energy?

? = v/r = 3.33/0.15 = 22.2 rad/s

Inertia = 1/2mr^2 = 0.5 x 2.6 x 0.15^2 = 0.0292 kg-m^2

Rotational KE = 1/2I?^2 = 0.5 x0.0292x 22.2^2 = 7.1954 J

c.)When the cylinder reaches the bottom of the ramp, what is its translational kinetic energy?

1/2mv^2

0.5 x 2.6 x 3.33^2 = 14.4155 J

When the cylinder reaches the bottom of the ramp, what is its total kinetic energy?

0.75mv^2 = mgh

mgh = 2.6 x 9.8 x 0.85 = 21.658 J

Translational KE =14.4155J

Rotational =7.1954J

Total KE =21.658J

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