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I have already answered Part A, as can be seen. I need part B. Light Refracted t

ID: 2096671 • Letter: I

Question

I have already answered Part A, as can be seen. I need part B.


Light Refracted through a Prism Light is incident along the normal to face AB of a glass prism of refractive index 1.48, as shown in the figure. (Figure 1) Find alpha max the largest value of the angle a such that no light is refracted out of the prism at face AC if the prism is immersed in air. Express your answer in degrees. Ignore any reflections from the surface BC. Find alpha max. the largest value the angle a can have without any light being refracted out of the prism at face AC if the prism is immersed in water (with index of refraction 1.33). Express your answer in degrees. Ignore any reflections from the surface BC.

Explanation / Answer

Let the ray makes an angle theta with the normal of the face AC


Apply the Snell law


npSin(theta) = nw*Sin(90) ----------(For Critical angle)


1.48*Sin(theta) = 1.33*1


Therefore



theta = 64 degree


Therefore


alpha = 90 - 64


= 26 degree

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