A 5.60 cm diameter wire coil is initially oriented so that its plane is perpendi

Question

1. A 5.60 cm diameter wire coil is initially oriented so that its plane is perpendicular to a magnetic field of 0.800 T pointing up. (Another way of saying this is that the normal to the coil's area is initially parallel to the magnetic field.) During the course of 0.110 s, the field is changed to one of 0.390 T pointing down. What is the magnitude of the CHANGE in the magnetic flux through this loop? (Use SI metric units, but just enter your answer as number, do not enter units).

1. I'm confused on how to solve this probelm, I've tried setting it up multiple times and keep getting it wrong, any help is much appreciated!

Explanation / Answer

initial flux=B1*A

=0.8*pi*(2.8*10^-2)^2

=1.97*10^3 Wb

final flux=B2*A

=0.39*pi*(2.8*10^-2)^2

=0.960*10^-3 Wb

here direction of magnetic field, So,the direction of flux is not changing,So final flux=

initial flux+final flux

=2.93*10^-3 Wb

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.