ALL NUMBERS ALREADY IN (WITH THE FUNNY MARKS AFTER) ARE CORRECT, IT IS ONLY THE

Question

ALL NUMBERS ALREADY IN (WITH THE FUNNY MARKS AFTER) ARE CORRECT, IT IS ONLY THE ONES WITH BLANK SPACES

1) How much work was done on the real system?
W = joules

2) What is the change in energy of the real system?
?(Ktot + U) = joules

3) What is (Ktot + U)final for the real system?
(Ktot + U)final = joules

4) What is the final speed of the center of mass of the real system?
vcm,final = m/s

5) What is the final vibrational energy of the real system (spring potential energy plus kinetic energy relative to the center of mass)?
(U + Krel)final = joules

Explanation / Answer

compare with this example.it will help you

Two identical 0.18 kg blocks (labeled 1 and 2) are initially at rest on a nearly frictionless surface, connected by an unstretched spring whose stiffness is 89 N/m, as shown in the upper diagram. Then a constant force of 8 N to the right is applied to block 2, and at a later time the blocks are in the new positions shown in the lower diagram. At this final time, the system is moving to the right and also vibrating, and the spring is stretched.

What is the change in energy of the real system?
What is (K_(tot)+U)_(final) for the real system?
What is the final translational kinetic energy of the real system?
What is the final speed of the center of mass of the real system?
What is the final potential energy of the real system? (Note that the spring is stretched.)
What is the final vibrational kinetic energy of the real system?

1) W=Fd
W = 8*.8 = 0.64
2) Same as before = 0.64
3) Ktrans = force*distance moved by center of mass
= 8*.7=0.56
4) v=(2Ktrans/m)^.5
v = (2*0.56/0.36)^.5
v = 1.76
5) U= .5kx^2
U = 0.5*89*0.02^2
U=0.0178
6) Kvib = W-U-Ktrans
Kvib = .64-0.0178-0.56
Kvib = 0.0622

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