A student attempts to make a simple generator by wrapping a long piece of wire a

Question

A student attempts to make a simple generator by wrapping a long piece of wire across a cylinder with a cross-section area of 1.241 x 10^-3 m^2. She then passes the coil between the poles of a horseshoe magnet with a magnetic field of 1.2 x 10^-2 T. The student finds that by removing the coil perpendicular to the magnetic field lines during 0.26s, an emf of 131 mV can be induced.

How many turns of wire are wrapped around the coil?

My attempt was wrong.

N= (0.131 V * 0.26 s)/( 1.2 x 10^-2 T *1.241 x 10^-3 m^2) = 2287.134 turns

Explanation / Answer

emf=Nd(flux)/dt

N=0.131*0.26/[(1.2 x 10^-2)*(1.241 x 10^-3)]=2287.1 turns

don't worry this is the only correct answer ,because the final flux will be equal to ZERO.PLz rematch your answer script with someone!!

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