Protons are projected with an initial speed vi = 9.28 km/s from a field-free reg

Question

Protons are projected with an initial speed vi = 9.28 km/s from a field-free region through a plane and into a region where a uniform electric field = ?720 N/C is present above the plane as shown in in the figure below. The initial velocity vector of the protons makes an angle ? with the plane. The protons are to hit a target that lies at a horizontal distance of R = 1.24 mm from the point where the protons cross the plane and enter the electric field. We wish to find the angle ? at which the protons must pass through the plane to strike the target. (a) What analysis model describes the horizontal motion of the protons above the plane? particle under constant velocity particle under constant acceleration particle in uniform circular motion particle in simple harmonic motion (b) What analysis model describes the vertical motion of the protons above the plane? particle under constant velocity particle under constant acceleration particle in uniform circular motion particle in simple harmonic motion (c) Argue that R = (vi^2 sin 2?i)/g would be applicable to the protons in this situation. (Do this on paper. Your instructor may ask you to turn in this work.) (d) Use R = (vi^2 sin 2?i)/g to write an expression for R in terms of vi, E, the charge and mass of the proton, and the angle ?. (Use the following as necessary: vi, e, E, ?, and mp for the mass of proton.) R = (e) Find the two possible values of the angle ?. (Enter your answers from smallest to largest.) answer (A) in degrees

Explanation / Answer

figure ???

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