You are asked to measure the moment of inertia of a large wheel, for rotation ab

Question

You are asked to measure the moment of inertia of a large wheel, for rotation about an axis through its center. Since you are a good physics student, you know what to do. You measure the diameter of the wheel to be 0.740 m and find that it weighs 280 N (note, that's not the mass!). You mount the wheel, using frictionless bearings, on a horizontal axis through the wheel's center. You wrap a light rope around the wheel and hang an 8.00 kg mass from the free end of the rope. See Figure 9.17 on p. 292 of the text for a similar situation. You release the mass from rest; the mass descends and the wheel turns as the rope unwinds. You find that the mass has a speed of 5.00 m/s after it has descended 2.00 m. (a) What is the magnitude of the linear acceleration of the 8.00 kg mass? (b) What is the magnitude of the angular acceleration of the wheel? (c) What is the magnitude of tension in the rope? (d) What is the magnitude of the torque on the wheel due to the rope? (e) What is the moment of inertia of the wheel for this axis?

Explanation / Answer

a) v^2 = u^2 + 2as where v is the velocity, a is acceleration and s is the distance after the mass has descended 2 metres v=5m/s , s= 2m so a= 25/4 = 6.25 m/ s^2 please rate me i am posting further answers too

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