This is my Physics lab assignment. I don\'t understand why my difference of forc

Question

This is my Physics lab assignment. I don't understand why my difference of force is so large. Trial 1 Trial 2 Trial 3 Trial 4 Radius of Rotation, r 0.18m 0.18m 0.18m 0.18m Displacement mass, md 0.950kg 0.950kg 0.950kg 0.950kg Displacement force, Fd 9.31N 9.31N 9.31N 9.31N Heavy mass, m (kg) 0.4478kg 0.4478kg 0.4478kg 0.4478kg Period of Rotation, T (s) 0.537 s 0.531s 0.523s 0.572s Speed of Rotation, v(m/s) 2.11 m/s 2.13 m/s 2.16 m/s 1.98 m/s Force, F 11.08N 11.29N 11.61N 9.76N Difference in Force (%) 15.97% 17.54% 19.81% 4.61%

Explanation / Answer

FOLLOW THIS The form of Coulomb's law is very similar to that for Newton's law of universal gravitation. What are the differences between these two laws? Compare also gravitational mass and electric charge. SOLUTION:The gravitational force is always attractive, and the magnitude of the force is: Gm1m2/r2. The electric force is attractive if the charges have opposite signs, and is repulsive if the charges have the same sign. The force magnitude is: kq1q2/r2. The gravitational and electric force are very similar in each having the inverse distance- squared rule, and in having the magnitudes depending in a linear and symmetric fashion on properties of the two objects. The major difference is that possibility of repulsion for the electric force. P2)Two charged smoke particles exert a force of 4.2 x 10-2 N on each other. What will be the force if they are moved so they are only one eighth as far apart? SOLUTION: F=kq1q2/r2 = 4.2 x10-2 N If r -> (1/8)r, r2 -> (1/64)r2 and so, F = 64(4.2 x 10-2 N) = 1.69 N P6)What is the repulsive electrical force between two protons in a nucleus that are 5.0 x10-15 m apart? SOLUTION: F = (9 x 109 Nm2/C2)(1.6 x 10-19 C)2 / (5.0 x10-15 m)2 = 9.2 N P8)A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -60

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