TABLE 10-1 EXHAIHT-GAR COMPOSTION AND AIR-FURL RATIOs Arm-FUEL RATIO TENT I ENGI
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TABLE 10-1 EXHAIHT-GAR COMPOSTION AND AIR-FURL RATIOs Arm-FUEL RATIO TENT I ENGINE CO CH. frotm Exhaust Ga Analysin RPM Cent Cent Cent Eight-Cylinder Valve-in-Head I Engine 11.3 10.6 13.6 15.2 13.1 11.1 12.2 0.3 13.8 12.8 11.9 11.1 13.9 15.6 13.1 11.4 12.6 10.7 13.7 13.4 11000 Full 2.1000 Full 9.9 0.0 7.2 3.30.3 .0 0.1 8.9 4.0 0.4 3.1000132 3 2204 0.3 4.1000Fu13.0 150.80.0 0.2 5..2000Ful 12.3 0.0 408 03 9.30.18.1 3.5 0.5 7..200011.00.05.2 2.0 0.4 7.8 0.2 10.5 5.50.2 9..2000ull13.0. 2.6 0.70.1 10..2000 Road 12.60. 3.3 0.1 8.2000 Full Bix-Cylinder L-Hend 8I Engine 1..1500 F 0. 431 0.2 2..1500Ful 12.3 0.1 3.4 0.9 0.5 3.. 1500 Full10.2 0.2 6.62.4 0.2 4..1500 Full 5..1500 Full 6..| 1500 | Full | 12.9 13.1 12.0 11.0 11.0 10.1 10.1 13.5 13.0 13.2 8.7 0.2 8.6 4.0 0.4 8.7 03 8.9 3.70.3 7.3 0.3 11.4 5.10.5 7.2 0.2 113 53 0.3 11.4 11.3 10.3 10.4 13.7 8..1500 Full 12.8 0.02.4 0.6 0.5 91500 Full 13.4 0.21.5 0.0 0.3 101500 Ful 13.6 0408 0.0 04 111500 Fu13.4 0.50.9 0.2 0.2 12.1500l13.313 06 0.2 0.1 13..1500l12.71.9 0.2 0.00.2 14.. 1500 Full24 2.90.0 0.0 02 14.6 15.0 15.5 16.1 15.0 15.6 16.5 17.2 *For fu? CaHu, data of Refereooe 1. 18. An SI engine burns fuel at the rate of 12 pounds per hour and exhausts inte a closed garege 100 ft long, 50 ft wide, and 20 ft high in which the temperature is 70 F and the atmoepherie pressure is 14.7 pia. How many minutes, approximately will it take for the engine to produce enough CO to be dangerous to life? Assume that 1 part of CO in 100,000 parte of air by weight is dangerous, and use the data of test 12 for a six-cylinder engine in Table 10-1Explanation / Answer
As air-fuel ratio is 15.5
Therefore 15.5 units of air contains 1 unit of fuel.
In one hour, engine consumes 12 pounds of fuel.
Lets divide these 12 pounds in compositions of fuel like CO2, O2, CO, H2 & CH4.
CO2 is 13.3% = 13.3% of 12 pounds is = 1.596 pounds
As we are interested in CO level, we will calculate for CO
CO is 0.6% = 0.6% of 12 pounds is = 0.072 pounds
According to Air-Fuel ratio,In one hour, if 12 pounds fuel consumed is 1 unit, then air consumed is 12 x 15.5.
Therefore amount of air consumed is 180 pounds.
It means, 0.072 pounds of CO is exhausted in 1 hr with 180 pounds of air.
As we know, 1 unit of CO is dangerous, therefore time to consume 180/0.072 pounds of air should be calculated.
0.072 x 14 = 1.008 (Dangerous limit)
180 x14 = 2520
Now, how much time it takes to consume 2520 pounds of air is needed to be calculated.
We know, in 1 hr = 180 pounds air consumed.
Therefore 14hrs approx is the time.
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