Using MATLAB: The velocity, v, and the distance, d, as a function of time, of a

Question

Using MATLAB:

The velocity, v, and the distance, d, as a function of time, of a car that accelerates from rest at constant acceleration, a, are given by

= a n d = 12

Determine v and d at every second for the first 10 seconds for a car with acceleration of = 15 ft/s2. Your output must have exactly the same format as the template table below. Note that dots have been added to the table below; you can count the dots to determine the exact spacings. Also note the units.

··········Time (s) ······· ···Distance (ft) ·········Velocity (mph) ··········x.x·················x.xxe+yy···············x.xxx

Explanation / Answer

MATLAB CODE

clear
clc;
a = 15; %ft/s2 (acceleration)
for i = 1:10
    t(i) = i; %time span
    d(i) = 12 + (1/2)*a*t(i)^2; % initial distane is 12 ft.
    v(i) = a*t(i)*(3600/5280); % 1 mile = 5280 ft and 1h =3600 sec
end
table = [t' d' v']

Ans

Time(s) Distance(ft) velocity (mph) 1.0000      19.5000 10.2273 2.0000    42.0000 20.4545 3.0000      79.5000 30.6818 4.0000     132.0000 40.9091 5.0000    199.5000 51.1364 6.0000    282.0000 61.3636 7.0000     379.5000 71.5909 8.0000     492.0000 81.8182 9.0000     619.5000 92.0455 10.0000    762.0000 102.2727

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