6.6 Anqular Momentum Equation (cont.) . Ex. 6.A6: y 50 m/s Determine the power p
ID: 2086530 • Letter: 6
Question
6.6 Anqular Momentum Equation (cont.) . Ex. 6.A6: y 50 m/s Determine the power produced by the sprinkler-like turbine shown in the sketch below. The turbine rotates in a horizontal plane about point O with a steady angular speed of 500 rpm. Water enters the turbine from a vertical pipe that is coaxial with the axis of rotation. Water exits the turbine through two identical nozzles, each of which has a section area of 10 cm2 The exit speed of the water is 50 m/s relative to the ?-50ms nozzle. Water density is 1000 kg/m3, and pressure at the exit of each nozzle is atmospheric. 90° 0.5 m ? 500 rpm Fluid Mechanics-- Chapter 6 30Explanation / Answer
Total mass flow out of control volume dm/dt = rho*A*V_rel
= 1000*(2*10*10^-4)*50
= 100 kg/s
Tangential velocity V_tang = 2*pi*r*N/60
= 2*3.14*0.5*500 / 60
= 26.17 m/s
Torque T = r*V_tang*(dm/dt)
= 0.5*26.17*100
= 1308.33 Nm
Power- = 2*pi*N*T/60
= 2*3.14*500*1308.33/60
= 68469.44 W
= 68.47 kW
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.