I do not get the difference between those two questions as a way of solving , Ca

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I do not get the difference between those two questions as a way of solving , Can anyone make the difference between the two clear ?

Like I dont S/M notation for Binary and not for Decimal Numbers . And what does it differ if we were told the numbers are signed or if we are told they are not signed ?

Thanks

Perform subtraction on the following unsigned numbers using 10's-complemnt of the subtrahend Where the result should be negative, 10's complement it and affix a minus sign. Verify your answers. (a) 7188-3049; (b) 150 - 2100; (c) 2997- 7992; (d) 1321 - 375 The following decimal numbers are shown in sign-magnitude form: +9826 and +801. Convert them to signed 10's complement form and perform the following operations. (Note that the sum requires six digits). (a) +9826) + (+801); (b) (+9826) (-801) (c) (-9826) + (+801); (d) (-9826) + (-801)

Explanation / Answer

For calculating 10's complement subtraction; we need to follow the simple rule;

Let the two nos are X and Y; so that we need to calculate X-Y in 10's complement method.

Step 1: subtract Y from highest possible 9's complement number

Step 2: Add 1 with it to make it 10's complement

Step 3: Add X with the above stated 10's complement no.

Step 4: if the above summation has carry, then the corresponding number is positive; hence ignore the carry and the rest will be the solution.

If the above summation has no carry, then the corresponding no is negative; hence find the out 9's complement of the no and add 1 to make it 10's complement and put a neagtive sign for getting the actual solution.

a) 7188 - 3049

Step 1: find 9's complement of 3049;

9999 - 3049 = 6950

Step 2: add 1

6950+1 = 6951 (10's complement no)

Step 3: Add 7188 with the above no

7188+6951 = 14139 which produce a carry; hence the no is positive; then the actual result is (4139)10.

b) 150 - 2100

Step 1: find 9's complement of 2100;

9999 - 2100 = 7899

Step 2: add 1

7899+1 = 7900 (10's complement no)

Step 3: Add 150 with the above no

7900+150 = 8050 which produce no carry; hence the no is negative; so we need to transfer the no into its 9's complement and add 1 to get the actual solution.

9999-8050 = 1949

1949+1 = 1950

then the actual solution is (-1950)10.

c) 2997-7992

Step 1: find 9's complement of 7992;

9999 - 7992 = 2007

Step 2: add 1

2007+1 = 2008 (10's complement no)

Step 3: Add 2997 with the above no

2997+2008 = 5005, which produce no carry; hence the no is negative; so we need to transfer the no into its 9's complement and add 1 to get the actual solution.

9999-5005 = 4994

4994+1 = 4995

then the actual solution is (-4995)10.

d) 1321-375

Step 1: find 9's complement of 375;

9999 - 375 = 9624

Step 2: add 1

9624+1 = 9625 (10's complement no)

Step 3: Add 1321 with the above no

1321+9625 = 10946 which produce a carry; hence the no is positive; then the actual result is (946)10.

a) if the two no is positive and we need to add them using 10's complement method; then simply add them is the solution;

(+9826)+(801) = (010627)10.

b) (+9826)+(-801) = 9826-801(do the same procedure as above)

Step 1: find 9's complement of 801;

999999 - 801 = 999198

Step 2: add 1

999198+1 = 999199 (10's complement no)

Step 3: Add 9826 with the above no

999199+9826 = 1009025 which produce a carry; hence the no is positive; then the actual result is (009025)10.

c) (-9826)+(+801) = 801 - 9826

Step 1: find 9's complement of 9826;

999999 - 9826 = 990173

Step 2: add 1

990173+1 = 990174 (10's complement no)

Step 3: Add 801 with the above no

990174+801 = 991975 which produce no carry; hence the no is negative;

compute 9's complement 999999 - 991975 = 008024

compute 10's complement (add 1) ; 008024 + 1 = 008025

the actual solution is (008025)10.

d) For adding two negative nos, it is very easy to calculate just add them and put a negative sign before result to get the actual solution;

(-9826) + (-801)

9826+801 = 010627

Then the actual solution is (-010627) 10.

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