The lower frequency limit of the commercial AM band is about 540 kHz. Determine
ID: 2083918 • Letter: T
Question
The lower frequency limit of the commercial AM band is about 540 kHz. Determine the wavelength. The so-called "Citizens Band" was originally referred to as the "11-meter band." Determine the frequency corresponding to this wavelength. An amplifier has a gain of 16 dB. Determine the absolute power gain. The output power from a long cable connection is only 4% of the input power. Determine the decibel loss. Consider the system of Problem 1-23 in the textbook with parameters shown and with impedances matched at all junctions. Determine (a) net system absolute gain, (b) net system decibel gain from the result of (a), and (c) net system decibel gain from individual decibel values. In the system of Problem 1-23, the signal source delivers an input power of 0.1 W as shown. Determine (a) the absolute power levels at each one of the junctions and (b) the power in dBm at each one of the junctions.Explanation / Answer
I can only answer the first question according to chegg guidelines.
1-1
As the wavelength of radio wave is given as =300/frequency in mhz
So here wavelength= 300/540*10^3*10^-6
=(300*10^3) / 540
= 0.55555*10^3
= 555.5 answer
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