5. A FHSS system uses MFSK modulation on base-band data. The FHSS scheme has fou
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Question
5. A FHSS system uses MFSK modulation on base-band data. The FHSS scheme has four channels of each of 1 MHz width, starts at 100 MHz and ends at 104 MHz. The hopping rate is 40 hops per second. The MFSK has baud rate of 20 symbols per second and 2 bits per symbol. The following data needs to be sent: 11 01 11 10. Is this fast hopping or slow hopping? Show the transmission frequencies using detailed diagram as shown in Chapter 9 Slides 13 and 14. Calculate the transmission frequency. Assume no guard band is necessary. The carrier frequency will be the center of the channel being used.its a fhss using mfsk
•In this example, M=4
•2-bit PN sequence determines the frequency “bin” for signal transmission, with a bin the input data determines the deviation
•MFSK bandwidth W_d=Mf_d
•FHSS bandwidth W_s=CW_d=4W_d (in this example)
•This figure is example of slow FHSS
Explanation / Answer
1.a) If I am transmitting a Frequency Hopping Spread Spectrum (FHSS) signal and the range of the FSSS frequency band is 40 kHz to 60 KHz, and if it is evenly divided into 20 sub-bands how much of an impact would an enemy have that is jamming 52 kHz? Would I still be able to reasonably communicate?
Communication will be impacted a bit, but you would receive 95% of your comms.
b) What if this enemy was eavesdropping on 52 kHz instead, would she obtain enough of my communication in a coherent way that I should be concerned?
No, she would only be receiving ~5% of the information and in a scrambled order.
2.a) If the bit rate of an FHSS system is 20 kbps, and the dwell time is 5 s on a frequency range of 25 MHz to 55 MHz, how many frequency shifts occur during the transmission of each bit?
Rb = 20kbps; Tb= 1/ 20X10^3= 50x10^-6
50us/bit x ( frequency shifts/5us) = 10 shifts/bit
b) What type of modulation scheme is used for FHSS.
FSK
BPSK
b) Compare chip time and bit time and describe how they relate to one another. How does this relationship affect the Bandwidth utilized?
The chip time must be smaller than the bit time in DSSS.
The bandwidth is dependent on the rate of the data, or ,. So the bandwidth of the spread spectrum signal is much larger than the bandwidth of the original signal.
The ratio is called the spreading factor or processing gain, and determines to a certain extent the upper limit of the total number of users supported simultaneously by a base station. In our book they define G= BW/fb- which is the same formula and the higher the gain, the greater the ability to fight interference.
10100111
The receiver obtained the following bit sequence:
01111000
What bit was being transmitted during this interval?
10100111
+ 01111000 Binary 1
11011111
b) What may have happened during the transmission of this signal to generate some uncertainty? Why are you still confident in the value you came up with?
One of the frequencies may have been jammed causing a bit error. Still 7 out of 8 were ones, so I am confident that binary 1 was the intended value.
1.a) If I am transmitting a Frequency Hopping Spread Spectrum (FHSS) signal and the range of the FSSS frequency band is 40 kHz to 60 KHz, and if it is evenly divided into 20 sub-bands how much of an impact would an enemy have that is jamming 52 kHz? Would I still be able to reasonably communicate?
Communication will be impacted a bit, but you would receive 95% of your comms.
b) What if this enemy was eavesdropping on 52 kHz instead, would she obtain enough of my communication in a coherent way that I should be concerned?
No, she would only be receiving ~5% of the information and in a scrambled order.
2.a) If the bit rate of an FHSS system is 20 kbps, and the dwell time is 5 s on a frequency range of 25 MHz to 55 MHz, how many frequency shifts occur during the transmission of each bit?
Rb = 20kbps; Tb= 1/ 20X10^3= 50x10^-6
50us/bit x ( frequency shifts/5us) = 10 shifts/bit
b) What type of modulation scheme is used for FHSS.
FSK
BPSK
b) Compare chip time and bit time and describe how they relate to one another. How does this relationship affect the Bandwidth utilized?
The chip time must be smaller than the bit time in DSSS.
The bandwidth is dependent on the rate of the data, or ,. So the bandwidth of the spread spectrum signal is much larger than the bandwidth of the original signal.
The ratio is called the spreading factor or processing gain, and determines to a certain extent the upper limit of the total number of users supported simultaneously by a base station. In our book they define G= BW/fb- which is the same formula and the higher the gain, the greater the ability to fight interference.
10100111
The receiver obtained the following bit sequence:
01111000
What bit was being transmitted during this interval?
10100111
+ 01111000 Binary 1
11011111
b) What may have happened during the transmission of this signal to generate some uncertainty? Why are you still confident in the value you came up with?
One of the frequencies may have been jammed causing a bit error. Still 7 out of 8 were ones, so I am confident that binary 1 was the intended value.
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