Given an 8-bit variable, YL, perform the multiplication: YL = YL * 10 Given two

Question

Given an 8-bit variable, YL, perform the multiplication: YL = YL * 10 Given two 8-bit variables stored in XL and YL, copy the value of bit position YL within variable XL into the carry flag. For example: If XL = 0x03 and YL = 0x00, set C to the value of bit 0 within XL. Since XL = 0x03 = 0000 0011_2, C = 1 If XL = 0xC2 and YL 0x04, set C to the value of bit 4 within XL. Since XL = 0xC2 = 1100 0011_2, C = 0 Note that: This operation is very similar to the bit test (BT) instruction in the x86 architecture. Since YL is not a constant, you cannot use the value of YL directly in any of the PIC bit test instructions (for example, btfsc XL, YL is not a valid instruction). Your code should not modify either XL or YL.

Explanation / Answer

4. YL=YL*10

YL= (YL*8)+(YL*2) = (YL*2*2*2)+(YL*2) = (YL <<3)+(YL<<1)

5. BT XL,YL

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