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The main characteristics of the Green Bank Telescope (GBT) are as follows: Fully

ID: 2082013 • Letter: T

Question

The main characteristics of the Green Bank Telescope (GBT) are as follows: Fully steerable antenna: +50 to +900 elevation range (-47 to +900 declination). Slew rates: Azimuth 35.2°/min, Elevation 17.6%min. Aperture: 100 m diameter. Unblocked aperture reduces sidelobes, RFI. Active surface compensates for gravitational and thermal distortions. Frequency coverage: 100 MHz to over 100 GHz. Location in the National Radio Quiet Zone with a comparatively low RFI environment Geocentric Latitude 38.24590630°, Longitude -79.83983858°, Radius 6370.74039207 km Geodetic Latitude 38.4331290, Height above ellipsoid/geoid 824.363/855.46 m. L-band receiver: 1.15-1.73 GHz, Lin/Circ pol., Tsys 20 K (Aperture efficiency 72%). S-band receiver: 1.73-2.60 GHz, Lin/Circ pol., Tsys 22 K (Aperture efficiency 72%). C-band receiver: 3.95-8.0 GHz, Lin/Circ pol., Tsys 18 K (Aperture efficiency 72%). X-band receiver: 8.0-10.1 GHz, Circ pol., Tsys 27 K (Aperture efficiency 71%).

Explanation / Answer

solution:

sample = bits per second

here 2 bits per second in one sample

800 million samples in each polarization meaning 800 * 106 / 2 bits in each polarization per second

which is equal to = 400 * 106 * 3600 in one hour

= 144* 1010 = 1.44 *1012 bits in one polarisation

so for both the polarisation no of bits in one hour = 2 * 1.44 * 1012 = 2.88 tera bits

but we want answer in terabyte so above value is divided by 8 will be an answer

So the no of terabytes storage = 2.88 / 8 = 0.36