The main characteristics of the Green Bank Telescope (GBT) are as follows: Fully
ID: 2082013 • Letter: T
Question
The main characteristics of the Green Bank Telescope (GBT) are as follows: Fully steerable antenna: +50 to +900 elevation range (-47 to +900 declination). Slew rates: Azimuth 35.2°/min, Elevation 17.6%min. Aperture: 100 m diameter. Unblocked aperture reduces sidelobes, RFI. Active surface compensates for gravitational and thermal distortions. Frequency coverage: 100 MHz to over 100 GHz. Location in the National Radio Quiet Zone with a comparatively low RFI environment Geocentric Latitude 38.24590630°, Longitude -79.83983858°, Radius 6370.74039207 km Geodetic Latitude 38.4331290, Height above ellipsoid/geoid 824.363/855.46 m. L-band receiver: 1.15-1.73 GHz, Lin/Circ pol., Tsys 20 K (Aperture efficiency 72%). S-band receiver: 1.73-2.60 GHz, Lin/Circ pol., Tsys 22 K (Aperture efficiency 72%). C-band receiver: 3.95-8.0 GHz, Lin/Circ pol., Tsys 18 K (Aperture efficiency 72%). X-band receiver: 8.0-10.1 GHz, Circ pol., Tsys 27 K (Aperture efficiency 71%).Explanation / Answer
solution:
sample = bits per second
here 2 bits per second in one sample
800 million samples in each polarization meaning 800 * 106 / 2 bits in each polarization per second
which is equal to = 400 * 106 * 3600 in one hour
= 144* 1010 = 1.44 *1012 bits in one polarisation
so for both the polarisation no of bits in one hour = 2 * 1.44 * 1012 = 2.88 tera bits
but we want answer in terabyte so above value is divided by 8 will be an answer
So the no of terabytes storage = 2.88 / 8 = 0.36
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.