Dont need the work just the answer A B C or D A simple magnetic circuit with pow
ID: 2079517 • Letter: D
Question
Dont need the work just the answer A B C or D
A simple magnetic circuit with power source and air gap has been represented in following figure. Calculate the magnetic flux density (B) in air gap, based on the given parameters: (cross section area of magnetic core) A = 5 times 10^-4 m^2 (coil turns) N=200 (current) I=12A (core dimensions) I_1 = 4cm I_2 = I_5 = 6cm I_3 = I_4 = 1.9cm I_g = 0.2cm (permeability of free space) mu 0 = 4 pi times 10^7 H/m (relative permeability of core) mu_r = 1200 3.34 3.183 1.437 7.183Explanation / Answer
We know that permeability =Flux density /Field intensity
Now Flux density B in air gap= permeability of air*NI/l
B=4*3.14*10^-7*200*12/(0.2*10^-4)=1.507
Hence option C is correct here
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