Equations E = hf = hc/lambda: c = 3.00 times 10^4 m/s: h = 6.63 times 10^-14 J m
ID: 2078540 • Letter: E
Question
Equations E = hf = hc/lambda: c = 3.00 times 10^4 m/s: h = 6.63 times 10^-14 J middot s 1 joule = 1 N middot m Using the equations and constants given above, calculate the Energy E (Energy or Energy per photon) of a sodium (Na) lamp if the wavelength is 590nm. Use your value for the Energy you calculated in joules (o Joules/1 photon) and the Equation E = mc^2 to calculate the mass of each photon. Draw the correct lewis dot structure for the product of following synthesis reaction: H + H rightarrow H_2 Correctly complete the Energy diagram for the above synthesis reaction in the diagram below.Explanation / Answer
solving 1st question
Energy=hc/wavelength
wavelength=590*10^(-9) m
we got Energy=3.37*10^(-19) J
(b) Energy=mc^2=3.37*10^(-19)
we got m=3.75*10^(-36) kg
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