Solar Rotation #1 Solar Rotation #2 Solar Rotation #3 I\'ve got three images sho

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Solar Rotation #1

Solar Rotation #2

Solar Rotation #3

I've got three images showing the Sun rotation from 1/12/16 through 3/22/16, with the time stamp in the lower left-hand corner.

In the images there are 4 solar features noted, labeled A,B,C, and D.  Given the radius of the Sun and the time the feature moves in the video, you are to calculate the velocity (km/s).

Our Sun has differential rotation, so each spot will differ in its speed. This is not computationally difficulty, explain your methodology in detail.

Now each post is going to have a different speed, certain areas have differential rotational it’s not the same speed as if it was a solid it’s a gasket surface so what you need to do is first figure out a scale so you want to open this video on your screen like I have it here and just take a ruler and measure this distance maybe its 10 centimeters it depends on your screen, then convert in Km.

Now noticed at the bottom of the screen here you have a number now this one is kind of hard to read but it’s something like 2016/01/24 and this is at 11:19 this is hours and minutes. So this particular picture was taken from the SoHo satellite at that particular time so if our want to measure how far it goes this particular spot moved the distance and with this timestamp how long it took to move that so say it moved six centimeters . So if it move six centimeters then you know the distance roughly in kilometers because you know once centimeter equals a certain amount of kilometers based on your scale.

So once you know the kilometers then you check at how much time has passed using the time stamp at the bottom here and you get km/s

So that is how you measure km/s for a given spot. Now if you notice on the screen you have four spots that you want measure for as pointed out on the pictures so for those four spots , show in detailed methodology as well as show all your calculations for those four spots want to see how fast those spots will be moving. They are not going to be moving the same as the sun rotates and each one will have a different km/s. The last immage shows the sun with a spot D at 4cnm from the left and 3cm from the top. at

Thank you!

There are actualy three figures ( the fourth one is identical with the third), 4 spots to calculate the speed for.

The speed we will be measuring is in kilometers/second. The diameter or radius listed online is equatorial - at the 'widest' point on your screen. If you are measuring a spot that is at a different latitude, you will have to create a scale for that width.

For instance, at the equator, the sun is 1.397 million kilometers. If the width of the sun on my screen is 15 centimeters, then the scale is 1 centimeter on my screen is equal to 93,133 kilometers (1.397 million divided 15).

Now if my spot moves from one time period to another a distance on my screen of 8 kilometers, that is then (according to my scale), it traveled 745,064 kilometers. if it did that in 2 days (which is 172,800 seconds), then the speed is 745,064 / 172,800 = 4.31 km/second. This is a fictitious example of course.

Thank you for your help!

Figures downloaded again: They represent the sun in each with spots on them. The first figure shows two spot on the sun A at about 1.5 cm from the upper left and 2 cm from top and B lower left at 1.75 and 2.5cm measured from the top of the sun, at 01:19 (time) on 2016/01/27. The second figure shows spot C at 3 cm from left and 3.5 from top of the sun, at 01:19 ( time) on 2016/02/10. And the last figure shows the sun with the spot D, located 4 cm from left and 3 cm from top at 01:19 ( time) on 2016/03/14.

If immages can't be viewed, I explained in detail what they are in the above last paragraph.

PS No immages needed, I explained everything in my paragraph. No need for picture. Use your imagination!

Explanation / Answer

Since each point represents different velocities, we have to calculate velocity at all points A,B,C and D.

In figure 1,

so, 1.5 cm from the upper left and 2 cm from the top.

Distance = 15(1.5^2+2^2)1/2

= 15*2.5*93,133 = 3492487.5 km

Time from 1/12/16 to 1/27/2016 (01:19) = 15 days, 1 hour and 19 sec = 1299619 sec

So, velocity at A = 3492487.5 /1299619 = 2.687 km/sec

At B,

distance = 15[1.75^2+2.5^2]1/2 = 15*3.05 cm

= 15*284055.65 = 4260834.75 km

Time = 1299619 sec

So, velocity at B = 4260834.75/1299619 = 3.278 km/sec

At C,

distance = 15[3^2+3.5^2]1/2 = 6439828.75 km

time feom 1/12/2106 to 2/10/2016 = 29 days, 1 hour and 19 sec = 2509219 sec

So, velocity at C = 6439828.75/2509219 = 2.566 km/sec

At D,

distance = 15[4^2+3^2]1/2 = 6984975.00 km

Time from 1/12/2016 to 3/14/2016 = 62 days, 1 hour and 19 sec = 5356819 sec

Velocity at D = 6984975/5356819 =1.304 km/sec

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