2. A 180 gram record with a 6 inch is minute. of the gram radius ng on a frictio
ID: 2077586 • Letter: 2
Question
2. A 180 gram record with a 6 inch is minute. of the gram radius ng on a frictionless barring at 45 revolutions per center record. beetle standing on the rim of the record. The beetle then walks halfway to the a) (2 points) what is the moment of inertia of the beetle-record system when the beetle is standing on the rim of the record? Beetle the angular momentum before the beetle walks halfway to the center of the b) (3 points) What c) hat is the kinetic energy of the beetle-record system before the beetle walks halfway to the center of the record?Explanation / Answer
a)
initial Moment of inertia is
I=(1/2)MR2+mR2=(1/2)*0.18*(6*0.0254)2+0.02*(6*0.0254)2
I=2.555*10-3 Kg-m2
b)
angular momentum
L=IW=(2.555*10-3)(45*2pi/60)
L=0.012 Kg-m2/s
c)
Kinetic energy
K=(1/2)IW2=(1/2)*(2.555*10-3)*(45*2pi/60)2
K=0.02837 J
d)
final moment of inertia
I=(1/2)*0.18*(6*0.0254)2+0.02*(6*0.0254/2)2=2.21*10-3 kg-m2
angular velocity
W=L/I=0.012/(2.21*10-3)=5.44 rad/sec or 51.93 rev/min
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