Interactive Learning Ware 18.2 provides one approach to solving problems such as

Question

Interactive Learning Ware 18.2 provides one approach to solving problems such as this one. The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q_1 = +7.65 mu C; the other two charges have identical magnitudes, but opposite signs: q_2 = 4.60 mu C and q_3 = +4.60 mu C. (a) Determine the net force (magnitude and direction) exerted on q_1 by the other two charges. magnitude N direction (b) If q_1 had a mass of 1.45 g and it were free to move, what would be its acceleration? magnitude m/s^2 direction An electric field of 244,000 N/C points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of -6.45 mu C at this spot? magnitude N

Explanation / Answer

Here ,

for the force between the charge q1 and q2

magnitude of force between charges q1 and q2

F12 = k * q1 * q2/d^2

F12 = 9 *10^9 * 7.65 *10^-6 * 4.60 *10^-6/1.30^2

F12 = 0.187 N

for the net force

net force on the charge q1 = 2 * F12 * sin(theta)

net force on the charge q1 = 2 * 0.187 * sin(23 degree)

net force on the charge q1 = 0.146 N

the net force on the charge q1 is 0.146 N

the direction of force is along y axis

b)

let the acceleration is a

1.45 *10^-3 * a = 0.146

a = 100.7 m/s^2

the magnitude of acceleration is 100.7 m/s^2

the direction of acceleration is along y axis

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.