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The magnitude of the tidal force between the International Space Station (ISS) a

ID: 2076649 • Letter: T

Question

The magnitude of the tidal force between the International Space Station (ISS) and a nearby astronaut on a spacewalk is approximately 2GmMa/r3 . In this expression, M is the mass of the Earth, r=6.79×106m is the distance from the center of the Earth to the orbit of the ISS, m=125kg is the mass of the astronaut, and a=19m is the distance from the astronaut to the center of mass of the ISS.

Problem 12.60 The magnitude of the tidal force between the International Space Station (ISS) and a nearby astronaut on a spacewalk is approximately 2GmMa/T3 n this expression, M s the mass of the Earth, r 6.79 x 106 m is the distance from the center of the Earth to the orbit of the ISS, m 120 kg is the mass of the astronaut, and a 20 m is the distance from the astronaut to the center of mass of the ISS Part A Calculate the magnitude of the tidal force for this astronaut. This force tends to separate the astronaut from the iss if the astronaut is located along the line that connects the center of the Earth with the center of mass of the ISS. Express your answer to two significant figures and include appropriate units. 13 m Submit My Answers Give Up incorrect, Try Again; 5 attempts remaining Enter your answer using dimensions of force. Part B Calculate the force of gravitational attraction between the astronaut and the ISS if they are 20 m apart and the ISS has a mass of 420,000 kg. Express your answer to two significant figures and include appropriate units Value Units Submit My Answers Give Up

Explanation / Answer

Magnitude of tidal force, F = 2GmMa/r^3

G = 6.67*10^-11 N.m^2/kg^2, m = 125 kg, M = 5.98*10^24 kg,

r = 6.79*10^6 m, a = 19 m

F = 2*6.67*10^-11*125*5.98*10^24*19/(6.79*10^6)^3

F = 6.052*10^-3 N

Part A

Magnitude of tidal force, F = 2GmMa/r^3

G = 6.67*10^-11 N.m^2/kg^2, m = 120 kg, M = 5.98*10^24 kg,

r = 6.79*10^6 m, a = 20 m

F = 2*6.67*10^-11*120*5.98*10^24*20/(6.79*10^6)^3

F = 6.1158*10^-3 N

Part B

Force of Gravitational attraction, F= GmM(Iss)/a^2

F = 6.67*10^-11*120*420000/20^2

F = 8.4042*10^-6 N