A 4.5 nC charge is located 3.2 m from a -2.8 nC charge. Find the electrostatic f

Question

A 4.5 nC charge is located 3.2 m from a -2.8 nC charge. Find the electrostatic force exerted by one charge on the other. Is the force repulsive, or attractive? The deoxyribonucleic acid (DNA) molecule is 2.17 mu m long. The ends of the molecule become singly ionized (negative on one end, positive on the other). The helical molecule acts like a spring, and compresses 1% upon becoming charged. What is the effective spring constant of the molecule? What is the electric field created by a proton at a distance of 5 m away from it? Note that the electric charge of a proton is e = 1.6 times 10^-19 C. What is the electric potential 1 cm from a proton? What is the electric potential difference between two points that are 1 cm and 2 cm from a proton? Sketch the electric field lines and equipotential lines for the following cases: (a) Positive charge, (b) Negative charge, (c) Positive and negative charge, (d) Positive charge and Negatively charged rectangular bar.

Explanation / Answer

1.

From Coloumb's law ,the force of attraction or repulsion between two charges is given by

F=K|Q1||Q2|/r2=(9*109)(2.8*10-9)(4.5*10-9)/3.22

F=1.107*10-8 N

since charges are opposite in sign ,the force is attractive

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