Do not use the answer that is already on chegg please. Need to see how to do the

Question

Do not use the answer that is already on chegg please. Need to see how to do the math.

1. Solar time is based on the apparent angular motion of the sun across the sky, with solar noon the time the sun crosses the meridian of the observer. It is also the time used in all of the sun-angle relationships; it does not coincide with local clock time. It is necessary to convert standard time to solar time by applying two corrections. First, there is a constant correction for the difference in longitude between the observer's meridian (longitude) and the meridian on which the local standard time is based. The sun takes 4 minutes to traverse 1° of longitude. The second correction is from the equation of time, which takes into account the perturbations in the earth's rate of rotation which affect the time the sun crosses the observer's meridian. The difference in minutes between solar time and standard time is: Solar time standard time 4 Lst Lloc E Standard Meridian for local time zone Local longitude of the location loc 110 degrees W W Local Lon Standard Meridian: 120 degrees W Mean value of the equation of time (EOT) for a given date. At Gato Grande, California, what is the solar time corresponding to 10:30 AM PST on April 17?

Explanation / Answer

to get the standard time we convert PST to GMT

then 10.30AM PST on April 17 means 17.30PM on April 17

standard time= 17.30PM

now EOT=9.87Sin(2B)-7.53Cos(B)-1.5sin(B)

where B=360/365(d-81)

d is the number of days calculating from January 1 as day 1 so April 17 means day 107

therefore, B=360/365(d-81)=360/365(107-81)=.986*26=25.636

then EOT=9.87Sin(2B)-7.53Cos(B)-1.5sin(B)

=9.87Sin(2*25.636)-7.53Cos(25.636)-1.5Sin(25.636)=9.87*.780-7.53*.901-1.5*.432

= .2706 min

Lst= 15degree*time difference between GMT and PST=15*7hr=105degree[15degree=360/24hr]

Lloc= local longitude of Gato Grande California=-110degree means it is located in the west of Greenwich (given)

then using given equation and substituting values we get

solar time- 17.30PM=4(105-(-110))+.2706min

or solar time=17.30PM+57.33HA+.2706min=17.30PM+3439.8min+.2706min=17.30PM+3440.07min=17.30+57.3345Hr

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