Let\'s examine the difference between absolute pressure and gauge pressure. A so

Question

Let's examine the difference between absolute pressure and gauge pressure. A solar water heating system uses solar panels on the roof, 12.0 m above the storage tank. The pressure at the level of the panels is 1 atm. What is the absolute pressure at the top of the tank? The gauge pressure? To find the absolute pressure p_tank at the tank, 12.0 m below the panels, we use the equation p = p_atm + pgh, with p = p_tank: p_tank = p_atm + pgh = (1.01 times 10^5 Pa) + (1.00 times 10^3 Kg/m^3)(9.80 m/s^2)(12.0 m) = 2.19 times 10^5 Pa. The gauge pressure is the amount by which p_tank exceeds atmospheric pressure-that is p_tank - p_atm: p_tank - p_atm = (2.19 - 1.10) times 10^5 Pa = 1.18 times 10^5 Pa = 1.16 atm = 17.1 lb/in.^2 = 17.1 psig If the tank has a pressure gauge, it is usually calibrated to read gauge pressure rather than absolute pressure. As have mentioned, the variation in atmospheric pressure over this is negligibly small. At what distance below the panels is the gauge pressure equal to 1.15 atm? Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

Assuming density of water=1000 kg/m(3)

Absolute presure at the top of tank =atmosphere pressure+(density*g*height)=101325+(1000*9.8*12)=218925 pa =2.16 atm

Gaugg pressure=difference in pressure=1.16 atm

Part A

Gaugg pressure =1.15 atm=(1000*9.8*h)/101325

We got h=11.89 m

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