The captain of spaceship A observes enemy spaceship E escaping with a relative v

Question

The captain of spaceship A observes enemy spaceship E escaping with a relative velocity of 0.48 c, as shown in the figure. A missile M is fired from ship A, with a velocity of 0.72 c relative to ship A. What is the relative velocity of approach of missile M, observed by the crew on ship E a) 0.34c b) 0.89c c) 0.37c d) 0.24c e) 0.30c 0. What is the energy of a photon that has a equal to the de Broglie of a proton having a speed of 7.1 times 10^4 m/s? a) 150 keV b) 440 keV c) 290 keV d) 360 keV e) 220 keV A metal surface with a work function of 2.5 eV is illuminated with light of various w a) NOT For which range of are emitted? a) 400 nm to 700 nm b) 400 nm to 500 nm c) 460 nm to 560 nm. d) 400 nm to 560 nm. e) 500 nm to 700 nm

Explanation / Answer

9) Applying velocity addition formula,

u = (u'-v) / 1-u'v / c2

Given Data ,u' = 0.72c

and v = 0.48c

Therefore

u = (0.72c - 0.48c) / [1-(0.72x0.48c2/c2)]

= 0.24c/[1-216/625]

= 0.24x625c/409

= 24x625c/40900

    = 0.37c --> Option C)

Q-10)

= h/mv

E = h = hC/ = hc / h / mv

E = m*v*C

E = (1.67*10^-27) * (7.1*10^4)* (3*10^8)

E = 3.557*10^-14 J

E = 3.557*10^-14 * (6.24210^15) keV

E = 222 keV = 220 keV (Option e)

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