Consider a bar, of length 3.5 m, shown in the figure, being acted on by three fo

Question

Consider a bar, of length 3.5 m, shown in the figure, being acted on by three forces. The magnitudes of the first two forces are 26 N and 23 N, and the first force is acting on the end of the bar at an angle of 59 degree as shown. What is the torque, in newton-meters, due to F_1 on this bar relative to the left end? Use a coordinate system with positive directed out of the screen. r_1 = What is the torque, in newton-meters, due to F on this bar relative to the left end, if this force is acting at the midpoint of the bar? Use a coordinate system with positive directed out of the screen. What is the magnitude of the force F_3, in newtons, if the force is a distance 0.45 m from the left end and the bar is not A rotating?

Explanation / Answer

a) Torque due to 1st force relative to first end = F1 * sin 59 * 3.5

= 26 * 0.857 * 3.5 = 78 N.m

b) Torque due to 2nd force relative to first end = F2 * 3.5/2

= 23 * 1.75 = 40.25 N.m

c) Forces are balanced at left end

F3 * d = 78 + 40.25

F3 = 78 + 40.25 / 0.45 m

F3 = 262.8 N.m

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