Figure shows an exploded drawing of a pump driven by a 4.4-kW, 3,453-pm motor in

Question

Figure shows an exploded drawing of a pump driven by a 4.4-kW, 3,453-pm motor integrally attached to a 4: 1 ratio gear reducer. Reducer shaft C is connected directly to pump shaft C. through a flexible coupling (not shown). Face A of the reducer housing is bolted to flange A' of the connecting tube (a one-picce solid uni), Pump face B is similarly aached to flange B: Determine the pump input torque. Submit your answer in N-m. gear reducer Motor Direction of rotation Connecting tube pump c These units are attached to A a fixed support.

Explanation / Answer

Motor power =P= 4.4 KW = 4400 W.

Motor speed =N= 3453 rpm.

Motor torque = T = Power / angulr velocity.

Angular velocity of motor = 2*3.14*3453 /60 = 361.414 rad/sec.

Motor torque = T = 4400/361.414 = 12.17 N-m.

Motor torque*gear ratio = Torque at pump.

12.17*(1/4) = Torque at pump.

Torque at pump = T = 3.0425 N-m

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