I am not sure how to complete this problem. A hydraulic system has a 100 gal res
ID: 2073708 • Letter: I
Question
I am not sure how to complete this problem.
A hydraulic system has a 100 gal reservoir mounted above the pump to produce a positive pressure (above atmospheric) at the pump inlet, as shown in the figure. The purpose of the positive pressure is to prevent the pump from cavitating when operating, especially at start-up. If the pressure at the pump inlet is to be 5 psi prior to turning the pump on and the oil has a specific gravity of 0.90, what should the oil level be above the pump inlet. Please give your answer in ft, but do not include the units in your response VENT RESERVOIR 5 psig PUMPExplanation / Answer
It is mentioned that the pressure prior to the pump inlet is 5 psig in order to avoid cavitation of the pump. We are asked to determine the oil level in the hydraulic reservoir to produce 5 psig pressure at the pump inlet.
Pressure is nothing but force per unit area, which is independent of the amount of liquid that has in hydraulic unit. It is an intrinsic property, independent of the mass.
Pressure = density * gravity*height.
Pressure = 5 psi = 720 psf ( pressure per square foot)
Density = sp.gravity * density of water = 56.185 lb/ft3.
Height = h ( in feet)
gravitational constant = g = 32.174 ft/sec2.
By substituting all the above values in formulae we get
720=56.185*32.174*h
height of fluid in reservoir to produce 5psi or 720 psf st pump inlet = h = 0.398 ft.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.