1. Make the following conversions. a. 367 g= kg b. 1.244 kg= g c. 125 mlliters d
ID: 207273 • Letter: 1
Question
1. Make the following conversions. a. 367 g= kg b. 1.244 kg= g c. 125 mlliters d. 0.876 liters e. 0.025gmg ml C-CF-32) x 5/9 Using the above formulas make the followving convensions. Show your work g, 37°C= h. 12° F 2. You are producing a machine tool in your factory that must be at least 35.25 mm. Five tools were randomly selected and measurod. The following measurements were obtained. 35.26,35.25, 35.31, 35.24, 35.27. What is the mean length of the five tools 3. Give a brief explanation of the standard deviation. while a non polar has a 4. With regard 10 charge, a polar compound is charge. 5. What reagent is used to determine the presence of proteins? 6. The reagent in question 5 binds to what bond in proteins 7. The building blocks of proteins are 8. what reagent is used to determine if simple sugars are present in a sample? 9. What reagent is used to test for complex carbohydrates? TO. What are the building blocks for complex carbohydrates? 11. How can one ascertain if one has a fat or lipid? Continued on the BackExplanation / Answer
1 Make the following conversions
a) 1kg =1000g Therefore, 1g = 0.001kg
367g = 367*0.001kg
=0.367kg
b) 1kg = 1000g
1.244kg = 1.244*1000g
=1244g
c) 1liters = 1000ml
125ml = 125*0.001 liters
=0.125 liters
d) 0.876 liters = 0.876*1000ml
=876ml
e) 1g = 1000mg
0.025g = 0.025*1000mg
=25mg
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.