What is the voltage across, the current in, and the power dissipated by each res

Question

What is the voltage across, the current in, and the power dissipated by each resistor in the two circuits shown below? Resistances are in Ohms. (A table format for your answers is suggested)

Explanation / Answer

Circuit 1: Let i1 be the total current, i2 be the current through R2 and i3 through R3. Equivalent resistance of the circuit = 6 x 12/18 + 4 = 8 ohms Hence, current i1 flowing through the circuit = V = IR => i1 = 1 amp Now, i1 = i2 + i3. Also, potential drop across R1 = 1 x 4 = 4 V. Hence, voltage across R2 and R3(same cuz they're in parallel) = 4 V, hence, i2 = 4/6 and i3 = 4/12 Circuit 2: This is a classic example of Kirchoff's Voltage and Current Laws, Divide the circuit into two loops (separated by r5). Let i5 pass through R5 (upward) and i4(left) through R4. Applying KVL to loop 1: 10 - i5 * R5 - i4 * R4 = 0; Similarly, for loop 2, 8 - i5 * R5 = 0 Hence, from equation 2, i5 = 0.5 A. Substituting in equation 1, i4 = 2 A Similarly, voltages can also be found out.

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