uire all thre all others are colorless. A colored plant is crossed with three te
ID: 207135 • Letter: U
Question
uire all thre all others are colorless. A colored plant is crossed with three tester plans with the following results: x aa RR produces 50% colored seeds x aa CC rr produces 25% colored seeds x AA cc rr produces 50% colored seeds What is the plant's genotype? Incorrect 0.00 points out of 1.00 17 Flag question Finish Answer: AC In the rat the allele for coat pigmentation (P) is dominant to the allele for no pigmentation (p). If there is pigment, black fur (B) is dominant to cream (b), but a h alleles at the B gene. If a homozygous black rat (PPBB) is crossed to a homozyous white rat with the cream alleles (ppbb) and the F1 offspring are interbred, what fraction of the F2 will have white coats? Not answered Points out of 1.00 Select one: a. 1/4 MacBook AirExplanation / Answer
1) Answer : AaCCRr
ACR are dominant alleles and all three dominant alleles should be present for a seed to become colored.
The genotype of plant is known but its phenotype is colored seed.
Cross 1 : A_C_R_ x aaccRR : 50 % colored seeds
Cross 2 : A_C_R_ x aaCCrr : 25 % colored seeds
Cross 3 : A_C_R_ x AAccrr : 50 % colored seeds
Possibilities of genotype :
1. AACCRR : If this is the genotype of plant, then in all the three cross, all seeds must be colored.
2. AaCcRr : If this is the genotype of plant, then in all the three cross, all seeds must be colored.
3. AaCCRR, AACcRR and AACCRr : All this three possibilities also results in 100 % colored seeds.
4. It can be any of the three possibilities, AACcRr, AaCcRR or AaCCRr but it is AaCCRr.
Cross1 : AaCCRr x aaccRR
2/4 x 1 x 1 = 50 %
Cross 2 : AaCCRr x aaCCrr
2/4 x 1 x 2/4 = 25 %
Cross 3 : AaCCRr x AAccrr
1 x 1 x 2/4 = 50 %
2) PPBB x ppbb
White coat = 4/16
Cream coat = 3/16
PB Pb pB pb PB PPBB PPBb PpBB PpBb Pb PPBb PPbb PpBb PPBB pB PpBB PpBb ppBB ppBb pb PpBb Ppbb ppBb ppbbRelated Questions
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