The figure below is a PV diagram for an ideal gas. Processes I, II, and III take

Question

The figure below is aPVdiagram for an ideal gas. Processes I, II, and III take place at constant volume, temperature, and pressure respectively. In process III the heat added to the gas is-58cal and the work done by the gas is-18cal.

(a) Find the change in internal energy for process III.

(b) FindQ,?U, andWfor process I.

The figure below is aPVdiagram for an ideal gas. Processes I, II, and III take place at constant volume, temperature, and pressure respectively. In process III the heat added to the gas is-58cal and the work done by the gas is-18cal. (a) Find the change in internal energy for process III. (b) FindQ,?U, andWfor process I.

Explanation / Answer

(a) III is an isobaric process. Heat added to the system = change in internal energy + work done by the gas => Change in internal energy = 58 - 18 = 40cal (b) I is isochoric process => change in volume = 0 =>work done = 0 => Q = ?U = n.c(v).?T = 40 cal

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.